You have 23.0g of water initially at -46°C. How much energy in joules is required to
heat the ice to 0°C? c ice = 2.1 J/g°C. I thought joules was calculated by grams*change in temperature*specific heat. The answer I get from 23*46*2.1 is 2221.8, but web assign says this is wrong, please help.

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  1. I calculated the same number as you; I suspect the problem is that you're reorting too many significnt figures. If you posted the problem EXACTLY as stated, then you're allowed only two places by the 2.1 and I would round the answer to 2.2E3 J. If that 2.1 is really 2.10 I would report the answer as 2.22E3

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  2. • A 50.0 g sample of ice at 0°C is melted. How much heat was absorbed by the ice?

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