Grant accelerates a 1kg ball 5.0m/s2 horizontally. The vertical acceleration of the ball is zero. The force of gravity is the only external force acting on the ball other than the forces Grant exerts on it.
a-How large is the horizontal force grant exerts on the ball at this instant to cause its 5.0m/s2 horizontal acceleration?
b-How large is the vertical force Grant exerts on the ball at this instant?
bobpursley answer is correct for the first one
but for b there is a vertical force of 9.81 because of the gravitational force
a- To find the horizontal force Grant exerts on the ball, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).
In this case, the mass of the ball is given as 1kg, and the horizontal acceleration is 5.0m/s^2. Therefore, the horizontal force Grant exerts on the ball can be calculated as:
F_horizontal = (1kg) * (5.0m/s^2)
F_horizontal = 5.0 N
So, the horizontal force Grant exerts on the ball is 5.0 Newtons.
b- Since the vertical acceleration of the ball is zero and the only external force acting on the ball (other than the forces Grant exerts) is the force of gravity, it means that the vertical force Grant exerts on the ball is equal in magnitude but opposite in direction to the force of gravity.
The force of gravity can be calculated as the mass of the ball multiplied by the acceleration due to gravity (g), which is approximately 9.8m/s^2 on the surface of the Earth.
F_gravity = (1kg) * (9.8m/s^2)
F_gravity = 9.8 N
So, the vertical force Grant exerts on the ball is 9.8 Newtons in the opposite direction of the force of gravity.
To determine the forces involved in the scenario, we can apply Newton's second law, which states that the net force applied to an object is equal to the product of its mass and acceleration.
a) The horizontal force Grant exerts on the ball can be calculated using the equation:
Force = mass × horizontal acceleration
Given that the mass of the ball is 1 kg and the horizontal acceleration is 5.0 m/s², we can substitute these values into the equation:
Force = 1 kg × 5.0 m/s²
Force = 5.0 kg·m/s²
Therefore, the horizontal force Grant exerts on the ball is 5.0 kg·m/s².
b) The vertical force Grant exerts on the ball can be determined by considering the gravitational force acting on the ball. The force of gravity is given by the equation:
Force of gravity = mass × acceleration due to gravity
Since the vertical acceleration is given as 0 m/s² and the force of gravity is the only external force acting vertically, the vertical force Grant exerts on the ball must be equal to the force of gravity. The gravitational force can be calculated using the equation:
Force of gravity = 1 kg × 9.8 m/s²
Force of gravity = 9.8 kg·m/s²
Therefore, the vertical force Grant exerts on the ball is 9.8 kg·m/s², which is equal to the force of gravity.
f=ma=1*5=5N
the ball moved only horizontally. Zero vertical force.
Your teacher is remarkably too easy.