Jorge is painting a rectangular mural. Its length is 2 ft less than twice its width. Its area is 264 ft2. Find the dimensions of the mural.

length = 2(width) - 2

l = 2w - 2

area = lw

area = (2w-2)(w)

264 = 2w^2-2w

0 = 2w^2 -2w-264

0= 2(w^2 - w -132)

divide both sides by 2

0 = w^2 - w - 132

Factor and solve for w. you only want the positive value since it is a width. Once you have the width, use l=2w-2 to find the length. Check by multiplying your length times the width to see if you get 264. Be sure to use your units of feet.

wedsa

I'm sorry, I don't understand what you mean by "wedsa". Can you please provide more context or rephrase your question or statement?

No

To find the dimensions of the mural, we can use the given information:

Let's assume the width of the mural as "x" feet.

According to the problem, the length is 2 feet less than twice the width, which can be expressed as (2x - 2).

Now, we know that the area of a rectangle is calculated by multiplying its length and width. So, we can set up an equation to find the dimensions:

Area = Length × Width

264 = (2x - 2) × x

Expanding the equation:

264 = 2x² - 2x

Setting the equation equal to zero:

2x² - 2x - 264 = 0

Now, to solve this quadratic equation, you can use various methods like factoring, completing the square, or using the quadratic formula. In this case, let's solve using factoring.

First, let's factor out a common factor of 2:

2(x² - x - 132) = 0

Next, let's factor the quadratic equation inside the parentheses:

2(x - 12)(x + 11) = 0

Now, we can set each factor equal to zero and solve for x:

x - 12 = 0 or x + 11 = 0

Solving for x:

x = 12 or x = -11

Since a negative width does not make sense in this context, we can disregard x = -11.

Therefore, the width of the mural (x) is 12 feet.

To find the length, we can substitute the value of x back into the expression for the length:

Length = 2x - 2 = 2(12) - 2 = 22 feet

So, the dimensions of the mural are 12 feet by 22 feet.