CH4+2O2----------CO2+2h2O
Use this balanced equation to calculate the mass of water formed when 32g of methane burns
mols CH4 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CH4 to mols H2O.
Now convert mols H2O to grams. That is grams H2O = mols H2O x molar mass H2O.
When carbon dioxide and carbon react the balanced equation is
CO2+C-________2CO
Calculate the mass of carbon monoxide formed from 4.4g of Carbon dioxide
Balanced equation :-
CH4(16g)+2O2(64g)--->CO2(44g)+2H2O(36g)
Here,16g CH4 produces 36g Water
So , the amount of water formed by the combustion of 32g CH4 = 36×32/16=72g.
Iquq
To calculate the mass of water formed when 32g of methane (CH4) burns, we need to use the balanced equation and stoichiometry.
The balanced equation represents the reaction between methane (CH4) and oxygen (O2) to form carbon dioxide (CO2) and water (H2O):
CH4 + 2O2 -> CO2 + 2H2O
From the equation, we can see that 1 mole of methane (CH4) reacts with 2 moles of oxygen (O2) to produce 2 moles of water (H2O).
Step 1: Convert the mass of methane to moles.
To do this, we need to know the molar mass of methane. Carbon has a molar mass of 12 g/mol, and hydrogen has a molar mass of 1 g/mol. The molar mass of methane (CH4) is calculated as:
(1 * 4) + 12 = 16 g/mol
To convert the mass of methane to moles, we divide the given mass by the molar mass:
32 g / 16 g/mol = 2 moles of CH4
Step 2: Use the stoichiometry of the balanced equation to determine the moles of water formed.
From the balanced equation, we know that 1 mole of methane (CH4) reacts to produce 2 moles of water (H2O).
Since we have 2 moles of CH4, we can say that:
2 moles CH4 * (2 moles H2O / 1 mole CH4) = 4 moles H2O
Step 3: Convert the moles of water to grams.
To do this, we need to know the molar mass of water. Hydrogen has a molar mass of 1 g/mol, and oxygen has a molar mass of 16 g/mol. The molar mass of water (H2O) is calculated as:
(2 * 1) + 16 = 18 g/mol
To convert the moles of water to grams, we multiply the moles by the molar mass:
4 moles of H2O * 18 g/mol = 72 g of H2O
Therefore, when 32g of methane burns, it will produce 72 grams of water.