A standard KHP solution is made by dissolving 2.12 grams of KHP in 100.00 mL of water. The KHP solution is then titrated with NaOH solution. It takes 23.12 mL of NaOH to reach the endpoint. What is the concentration of the NaOH?
KHP + NaOH ==> NaKP + H2O
mols KHP = grams KHP/molar mass KHP
Since 1 mol KHP reacts with 1 mol NaOH, you know mols NaOH = mols KHP
Then M NaOH = mols NaOH/L NaOH. You know mols NaOH and L NaOH, calculate M NaOH
To find the concentration of NaOH, we need to use the equation for the reaction that occurs between KHP (Potassium Hydrogen Phthalate) and NaOH (Sodium Hydroxide).
The balanced equation for the reaction is:
KHP + NaOH → KNaP + H2O
From the balanced equation, we can see that one mole of KHP reacts with one mole of NaOH to form one mole of KNaP and one mole of water.
Now, let's calculate the number of moles of KHP used in the titration:
Given mass of KHP = 2.12 grams
Molar mass of KHP (C8H5KO4) = 204.23 g/mol
Using the formula: Moles = Mass / Molar mass
Moles of KHP = 2.12 g / 204.23 g/mol = 0.0104 mol
Since the reaction is stoichiometric, the number of moles of NaOH used in the titration is also 0.0104 mol.
Now, let's calculate the concentration of NaOH in moles per liter (Molarity):
Volume of NaOH used = 23.12 mL = 0.02312 L
Molarity (M) = Moles / Volume
Molarity of NaOH = 0.0104 mol / 0.02312 L = 0.449 M
Therefore, the concentration of NaOH is 0.449 M.