chemistry

What is the ph of 0.25 M tartaric acid? Ka=2.5*10^-5M

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  1. Tartatic acid = H2T
    ........H2T ==> H^+ + HT-
    I......0.25......0.....0
    C........-x......x.....x
    E......0.25-x....x.....x

    Substitute the E line into Ka expression and solve for x = (H^+), then convert to pH.
    This looks like the wrong Ka for the acid.

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