I was given this info

r=1.5 m
d=3 m
F= 50 N
angle= 110 degrees

3. The attempt at a solution
T=Fsin
T= (1.5)(50)sin(110)
T=70 J

How do i get (maximum) torque?

To calculate the (maximum) torque, you need to consider two factors: the magnitude of the force applied and the perpendicular distance from the point of rotation (pivot) to the line of action of the force.

Here's how you can calculate the (maximum) torque:

1. Identify the force vector and its angle: In this case, you were given a force of 50 N and an angle of 110 degrees. It means that the force is applied at an angle of 110 degrees with respect to the reference line.

2. Resolve the force vector: By using trigonometry, you can determine the vertical component of the force (perpendicular to the reference line) and the horizontal component of the force (parallel to the reference line). In this case, you are interested in the vertical component of the force because it is the one that contributes to the torque.

3. Calculate the perpendicular distance: Here, you were given the perpendicular distance, which is the value of "r" or 1.5 m.

4. Calculate the torque: The torque (τ) is calculated by multiplying the perpendicular distance (r) and the vertical component of the force (Fsinθ). Therefore, the formula for the torque is τ = r * Fsinθ.

Applying the formula using the given values, you can calculate the (maximum) torque:

τ = (1.5 m) * (50 N * sin(110°))
τ = (1.5 m) * (50 N * -0.9397)
τ ≈ -70 Nm (rounded to two decimal places)

Note that the negative sign indicates the direction of the torque, which is opposite to the direction of rotation in this case. The magnitude of the torque is 70 Nm.