another question that confyses me is solve3x^2-4x=15
would the answer be 5,3
3 x^2 - 4 x -15 = 0
(x-3)(3x+5) =0
x = 3
x = -5/3
3X=B
To solve the equation 3x^2 - 4x = 15, there are a few steps you can follow:
Step 1: Set the equation equal to zero by subtracting 15 from both sides:
3x^2 - 4x - 15 = 0
Step 2: Factor the quadratic equation if possible. In this case, the equation cannot be factored easily, so we move on to the next step.
Step 3: Use the quadratic formula to find the solutions. The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
For the equation 3x^2 - 4x - 15 = 0:
a = 3
b = -4
c = -15
Substituting these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)^2 - 4(3)(-15))) / (2(3))
= (4 ± √(16 + 180)) / 6
= (4 ± √196) / 6
= (4 ± 14) / 6
Simplifying further:
x = (4 + 14) / 6 = 18/6 = 3
x = (4 - 14) / 6 = -10/6 = -5/3
So the solutions to the equation 3x^2 - 4x = 15 are x = 3 and x = -5/3. Therefore, the answer is not just 5 and 3, but rather 3 and -5/3.