A train is traveling west with a force of 820 N, and then the conductor applies the brakes with a force of 500 N. What is the resulting net force on the train?
This problem is poorly presented in so many ways.
trains don't travel with a force, but rather a speed. If the speed is constant, then the net force is zero.
When the conductor applies the brakes with a force of 500N, is that the force of his foot on the control, or the force of the brakes on the wheels, or what?
However, . . .
If the train is accelerating due to a westward force of 820N, and the brakes apply a net eastward force of 500N, then the resultant force acting on the train is clearly 320N westward.
well you need energy only for the train to go.
To find the resulting net force on the train, you need to consider the direction of the forces. In this case, the force of the train traveling west and the force of the brakes are in opposite directions.
To calculate the net force, you'll need to subtract the force of the brakes from the force of the train. Since the force of the train is traveling west and the force of the brakes is opposing its motion, you can subtract the force of the brakes from the force of the train.
The resulting net force on the train can be calculated using the equation:
Net force = Force of the train - Force of the brakes
Given that the force of the train is 820 N and the force of the brakes is 500 N, you can substitute these values into the equation:
Net force = 820 N - 500 N
Net force = 320 N
Therefore, the resulting net force on the train is 320 N.