# Algebra II

what is an equation of a parabola with the given vertex and focus? Vertex: (-2,5); focus: (-2,6)

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1. a parabola with focus at (0,p) and directrix at y = -p is

x^2 = 4py

The vertex is midway between the focus and directrix, so your parabola has p = 1

x^2 = 4y

Now shift things so the vertex is at (-2,5) and you have

(x+2)^2 = 4(y-5)

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