1. A
2. A body with a mass of 490kg is pulled along a horizontal plane at a constant velocity.the pulling force is 1.2 kN is making an angle of 20degrees with the plane.
A.determine the coefficient of friction
3.a force of 318.123N accelerates a car at 3m/s^2 from rest for 10seconds
Calculate the following
A. Mass of the car
B.momentum of the car after 10 seconds
C.velocity of the car after 10seconds
Please help me guys
First question
1.A car moves at a constant velocity up an inclined plane making an angle of 28degrees with the horizontal. The coefficient of friction is 0.387. The force exerted by the engine on the car is 588N.
Calculate the Following
A.weight of the car
B.frictional force acting on the car
2. M*g = 490 * 9.8 = 4802 N. = Wt. of the body.
Fn = Mg-Fap*sin A = 4802-1200*sin20 =
4392 N = Normal force.
Fx-Fs = M*a
1200*Cos20 - Fs = M*0
1128 - Fk = 0
Fk = 1128 N. = Force of kinetic friction
u = Fk/Fn = 1128/4392 = 0.257
3A. F = M*a
F = 318.1 N.
a = 3 n/s^2
M = mass in kg.
Solve for M
C. V = Vo + a*t
Vo = 0
a = 3 m/s^2
t = 10 s.
Solve for V.
B. Momentum = M*V
Sure! I can help you with those questions.
1. To determine the coefficient of friction, we need to use the given information "A body with a mass of 490kg is pulled along a horizontal plane at a constant velocity, and the pulling force is 1.2 kN making an angle of 20 degrees with the plane."
The force of friction can be calculated using the formula: Frictional force = (coefficient of friction) * (normal force).
Since the body is at a constant velocity, the frictional force must be equal to the applied pulling force. The normal force in this case is equal to the weight of the object, which is given by the formula: Normal force = mass * gravity, where gravity is approximately 9.8 m/s².
The applied force can be resolved into two components, one perpendicular to the plane (normal force) and one parallel to the plane (frictional force). The parallel component of the applied force is given by the formula: Force parallel = applied force * sin(angle).
Now we can set up the equation:
Force of friction = Force parallel
(coefficient of friction) * (normal force) = applied force * sin(angle).
Substituting the given values:
(coefficient of friction) * (mass * gravity) = (1.2 kN) * sin(20).
Simplifying the equation and solving for the coefficient of friction will give you the answer.
2. For this question, we are given the following information:
- Force (F) = 318.123 N
- Acceleration (a) = 3 m/s^2
- Time (t) = 10 seconds
A. To calculate the mass of the car, we can use Newton's second law of motion: Force = mass * acceleration. Rearranging the formula, we get mass = force / acceleration. Plugging in the given values, we have mass = 318.123 N / 3 m/s².
B. To calculate momentum, we can use the formula: Momentum = mass * velocity. Since the car starts from rest and accelerates for 10 seconds, the final velocity can be calculated using the formula: velocity = initial velocity + (acceleration * time). Since the car starts from rest, the initial velocity is 0. Substituting the given values, we have momentum = mass * (acceleration * time).
C. To calculate velocity, we can use the same formula mentioned in the previous step: velocity = initial velocity + (acceleration * time). Plugging in the given values, we have velocity = 0 + (acceleration * time).
By substituting the values for acceleration and time, you can calculate the mass, momentum, and velocity of the car after 10 seconds.