If 3•5/9 and 40•1/2 are the 1st and last term of geometric sequence. Determine the value of fifth term if there are seven terms.
3 5/9 = 32/9
40 1/2 = 81/2
So, the common ratio,
r^6 = (32/9)/(81/2) = 64/729
r = 2/3
T5 = 32/9 * (2/3)^4
40 1/2 = 81/2
So, the common ratio,
r^6 = (32/9)/(81/2) = 64/729
r = 2/3
T5 = 32/9 * (2/3)^4