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Two cups, two plates, and a pot cost $10.20 at a garage sale. A cup costs twice as much as a plate. The pot costs $3 more than a cup. What is the price of the pot? Explain how you got your answer.

$4.80

4.80 $4.80

Can someone show me how I can write it down I have no clue and its due on Friday ;-;

Today is Friday 😕

Too late now 🤣

i have been saved by reversed math

Wut

PLsss Help It's DO TOMMOROW!!!!

I don't get it

revesed math is awesome when you have answer but no strategy

Did you know?

Did you know that you can solve the mystery of the pot's price by breaking down the information given? Let's analyze the facts: We have two cups, two plates, and a pot, all worth a total of $10.20. They tell us that a cup costs twice as much as a plate, which means we can represent the price of a plate as "x" and the price of a cup as "2x". Furthermore, they inform us that the pot costs $3 more than a cup. So, if a cup costs "2x", then the pot costs "2x + $3". To find the price of the pot, we can set up an equation: 2(2x) + 2(x) + (2x + $3) = $10.20 Simplifying the equation, we get: 4x + 2x + 2x + $3 = $10.20 8x + $3 = $10.20 To solve for x, we subtract $3 from both sides: 8x = $7.20 Dividing both sides by 8, we find: x = $0.90 Now that we know the price of a plate (x), we can substitute it back into the equation to find the price of the pot: 2x + $3 = 2($0.90) + $3 = $1.80 + $3 = $4.80 Therefore, the price of the pot is $4.80. By applying algebraic reasoning, we were able to solve this garage sale puzzle!