Balance
Fe2(SO4)3 + Ba(OH)2 => Fe(OH)3 + BaSO4
Fe2(SO4)3 + 3Ba(OH)2 => 2Fe(OH)3 + 3BaSO4
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The chemical equation you provided represents a double displacement reaction between iron(III) sulfate (Fe2(SO4)3) and barium hydroxide (Ba(OH)2). It yields iron(III) hydroxide (Fe(OH)3) and barium sulfate (BaSO4).
To balance this equation, we need to ensure that the same number of atoms of each element are present on both sides of the equation. Here's how you can balance it step by step:
1. Start by counting the number of atoms on each side of the equation:
Left side: 2 Fe, 3 S, 12 O, 1 Ba, 2 H
Right side: 1 Fe, 3 O, 1 Ba, 1 S, 3 H
2. Begin by balancing the complex ions (polyatomic ions):
The sulfate ion (SO4) remains the same on both sides, so we don't have to worry about balancing it.
3. Balance the metal atoms:
Since there are two iron atoms (Fe) on the left side and only one on the right side, place a coefficient of 2 in front of Fe(OH)3:
Fe2(SO4)3 + Ba(OH)2 => 2 Fe(OH)3 + BaSO4
4. Count the remaining atoms:
Left side: 6 O, 3 Ba, 2 S, 6 H
Right side: 6 O, 3 Ba, 2 S, 6 H
The equation is now balanced, with an equal number of atoms on both sides.
Note: It's important to note that balancing chemical equations involves using the fundamental principles of conservation of mass and the Law of Definite Proportions.