A force t=312n up and incline is reward to keep a body at rest on a fritionless inclined plane which make an angle of 35degress with horizontal. Draw a force diagram and label all the force acting on a body. Calculate the magnitude of the force due to gravity and the normal force
energy
Fp = Mg*sin35 = 315
Mg = 315/sin35 = 549 N. = Force of gravity.
Fn = Mg*Cos35 = 549*Cos35 = 450 N. = Normal force.
To draw a force diagram for the given scenario, we need to consider the forces acting on the body.
1. Force of gravity (Fg): This force is always acting downward, vertically. It can be calculated using the formula Fg = m * g, where m is the mass of the body and g is the acceleration due to gravity (approximately 9.8 m/s^2).
2. Normal force (N): This force is perpendicular to the inclined plane and acts perpendicular to the contact surface between the body and the inclined plane. It counterbalances the force of gravity and prevents the body from sinking into the plane. In this case, the body is at rest, so the magnitude of the normal force (N) is equal to the magnitude of the force of gravity (Fg).
3. Applied force (Fa): This force is given in the question statement. It is acting upward along the incline and has a magnitude of 312 N.
Now, let's calculate the magnitude of the force of gravity (Fg) and the normal force (N):
Given:
Angle of incline (θ) = 35 degrees
Force applied (Fa) = 312 N
Mass of the body (m) = ?
To calculate the magnitude of the force of gravity (Fg), we need the mass of the body. If the mass is not given, we cannot calculate Fg. You will need that information to proceed with the calculation.
To calculate the normal force (N), we can use the magnitude of the force of gravity (Fg) since the body is at rest and the normal force is equal to the force of gravity in this situation.
Hence, to find the answers, we need to know the mass of the body.