Describe an infinte geometric series with a beginning vaule of 2 that converges to 10. What are the first 4 terms of the series?

I know r=4/5

Now what do I do

just plug and chug.

4/(1-r) = 10
2/5 = 1-r
r = 3/5

So, now you know the G.P.

To find the first 4 terms of the infinite geometric series with a beginning value of 2 and a common ratio of 4/5 that converges to 10, you can use the formula for the general term of a geometric series:

š‘Žš‘› = š‘Žā‚ * š‘Ÿ^(š‘›āˆ’1)

where š‘Žš‘› is the š‘›-th term of the series, š‘Žā‚ is the first term, š‘Ÿ is the common ratio, and š‘› is the position of the term in the series.

In this case, š‘Žā‚ = 2 (the first term) and š‘Ÿ = 4/5 (the common ratio).

To find the first term, substitute š‘› = 1 into the formula:

š‘Žā‚ = 2 * (4/5)^(1-1)

Simplifying this, we have:

š‘Žā‚ = 2 * (4/5)^0
= 2 * 1
= 2

Therefore, the first term (š‘Žā‚) of the series is 2.

To find the second term, substitute š‘› = 2 into the formula:

š‘Žā‚‚ = 2 * (4/5)^(2-1)
= 2 * 4/5
= 8/5
= 1.6

So, the second term (š‘Žā‚‚) of the series is 1.6.

Similarly, you can find the third term (š‘Žā‚ƒ) and the fourth term (š‘Žā‚„) by substituting š‘› = 3 and š‘› = 4 into the formula.