Describe an infinte geometric series with a beginning vaule of 2 that converges to 10. What are the first 4 terms of the series?
I know r=4/5
Now what do I do
just plug and chug.
4/(1-r) = 10
2/5 = 1-r
r = 3/5
So, now you know the G.P.
To find the first 4 terms of the infinite geometric series with a beginning value of 2 and a common ratio of 4/5 that converges to 10, you can use the formula for the general term of a geometric series:
šš = šā * š^(šā1)
where šš is the š-th term of the series, šā is the first term, š is the common ratio, and š is the position of the term in the series.
In this case, šā = 2 (the first term) and š = 4/5 (the common ratio).
To find the first term, substitute š = 1 into the formula:
šā = 2 * (4/5)^(1-1)
Simplifying this, we have:
šā = 2 * (4/5)^0
= 2 * 1
= 2
Therefore, the first term (šā) of the series is 2.
To find the second term, substitute š = 2 into the formula:
šā = 2 * (4/5)^(2-1)
= 2 * 4/5
= 8/5
= 1.6
So, the second term (šā) of the series is 1.6.
Similarly, you can find the third term (šā) and the fourth term (šā) by substituting š = 3 and š = 4 into the formula.