Heat
A.5kg of steel is cooled down in oil and the temperature drops from 900 degrees celsius to 27degrees celsius. The specific heat capacity of steel is 460J/kg degrees Celsius and that of oil 1.5kJ/kg degrees Celsius
Calculate the following:
1.quantity of heat lost by steel
2.mass of oil required if the original temperature of the oil is 18 degrees Celsius
To calculate the quantity of heat lost by the steel and the mass of oil required, we can use the formula:
Q = m * c * ΔT
Where:
Q is the quantity of heat
m is the mass
c is the specific heat capacity
ΔT is the change in temperature
1. Quantity of heat lost by steel:
Given:
Mass of steel, m = 5 kg
Specific heat capacity of steel, c = 460 J/kg°C
Change in temperature, ΔT = 900°C - 27°C = 873°C
Plugging the values into the formula:
Q = 5 kg * 460 J/kg°C * 873°C
Q = 2,383,550 J
Therefore, the steel loses 2,383,550 Joules of heat.
2. Mass of oil required:
To calculate the mass of oil required, we need to rearrange the formula:
m = Q / (c * ΔT)
Given:
Quantity of heat lost by the steel, Q = 2,383,550 J
Specific heat capacity of oil, c = 1.5 kJ/kg°C = 1500 J/kg°C
Change in temperature, ΔT = 900°C - 18°C = 882°C
Plugging the values into the formula:
m = 2,383,550 J / (1500 J/kg°C * 882°C)
m ≈ 1.7 kg
Therefore, you would require approximately 1.7 kg of oil if the original temperature of the oil is 18°C.
To calculate the required values, we will use the following formula:
Q = mcΔT
where:
Q = quantity of heat
m = mass
c = specific heat capacity
ΔT = change in temperature
1. Quantity of heat lost by steel:
We have the following information:
m_steel = 5 kg (mass of steel)
c_steel = 460 J/kg°C (specific heat capacity of steel)
ΔT_steel = 900°C - 27°C = 873°C (change in temperature of steel)
Using the formula Q_steel = m_steel * c_steel * ΔT_steel, we can find the quantity of heat lost by steel:
Q_steel = 5 kg * 460 J/kg°C * 873°C
Q_steel = 2,003,100 J (or 2.0031 MJ)
Therefore, the quantity of heat lost by the steel is 2,003,100 Joules (or 2.0031 MegaJoules).
2. Mass of oil required if the original temperature of the oil is 18 degrees Celsius:
We have the following information:
ΔT_oil = 900°C - 18°C = 882°C (change in temperature of oil)
c_oil = 1.5 kJ/kg°C = 1500 J/kg°C (specific heat capacity of oil)
Let's assume m_oil is the mass of oil required.
Using the formula Q_oil = m_oil * c_oil * ΔT_oil, we can rearrange it to solve for the mass:
m_oil = Q_oil / (c_oil * ΔT_oil)
Substituting the known values, we get:
m_oil = Q_oil / (1500 J/kg°C * 882°C)
Since we don't have the quantity of heat (Q_oil) provided, we cannot calculate the mass of oil required without that information.