hakiim invested 15000 he put part of it in a term deposit that paid 4% per annum and the remainder in a treasury bill that paing 5% per annum after one year the total interest was 690 how much did hakiim invest at each rate

if there is $x at 4%, then the rest (15000-x) is at 5%.

Now just add up the interest and solve for x:

.04x + .05(15000-x) = 690

To solve this problem, let's assume that Hakiim invested "x" dollars in the term deposit at a 4% interest rate. Since he invested a total of $15,000, the amount invested in the treasury bill would be the remaining amount, which is "15000 - x" dollars.

Now, we can calculate the interest earned from each investment. The interest earned from the term deposit is given by "x * 0.04" (since 4% can be written as 0.04), and the interest earned from the treasury bill is "(15000 - x) * 0.05" (since 5% can be written as 0.05).

According to the problem, the total interest earned was $690, so we can set up the equation:

x * 0.04 + (15000 - x) * 0.05 = 690

Now, let's solve this equation to find the value of "x":

0.04x + 0.05(15000 - x) = 690
0.04x + 750 - 0.05x = 690
-0.01x = -60
x = -60 / -0.01
x = 6000

Therefore, Hakiim invested $6000 in the term deposit (4% interest rate) and $9000 (15000 - 6000) in the treasury bill (5% interest rate).