There are 24 students in Ms. Messing's class. Six more students walk to school than ride their bikes. The number of students that ride their bikes is the

same as the number of students that are driven to school. How many students walk to school?

Please only use addition and subtraction.

B= ride bikes

W = walk
D = driven to school
==================
W = B+6
B = D
W + B + D = 24
For D you can substitute B
For W you can substitute B + 6
Do that and solve for B.

@DrBob

Do 3rd graders know algebra?

I don't know but Dawn said use only addition and subtraction and that's what I did.

To solve this problem using only addition and subtraction, we can break it down step by step:

Step 1: Let's assume the number of students who ride their bikes is x.

Step 2: According to the problem, the number of students driven to school is also x.

Step 3: Since the problem states that six more students walk to school than ride their bikes, we can express the number of students who walk as (x + 6).

Step 4: Now, let's add up the total number of students. The students who ride bikes (x) plus the students driven to school (x) plus the students who walk to school (x + 6) should sum up to the total number of students in the class, which is 24.

So, we can set up the equation: x + x + (x + 6) = 24.

Continuing with addition and subtraction:

2x + x + 6 = 24
3x + 6 = 24

To isolate x, we subtract 6 from both sides:

3x = 24 - 6
3x = 18

Lastly, we divide both sides by 3:

x = 18 / 3
x = 6

Now that we have the value of x, which represents the number of students who ride their bikes, we can find the number of students who walk by substituting x into (x + 6):

x + 6 = 6 + 6 = 12

Therefore, 12 students walk to school.