trig

An airplane is traveling at a speed of 724 km per hour at a bearing of N30°E. If the wind velocity is 32 km per hour from the west, find the resultant speed and direction of the plane.

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  1. Vp= 724(cos(60), sin(60))
    = 724 (1/2 , (√3)/2)
    = (362, 362√3)
    Vw = 32(cos(0), sin(0))
    = (32, 0)
    VR = (√394^2 + (362√3)^2))
    = 740.5 km/h
    tanθ = (362√3)/394
    θ = tan^-1(362√3)/394)
    θ = 57.85 degree
    N = 32.15 degree

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