Two carts are involved in an elastic collision. Cart A with mass 0.55 kg is moving towards Cart B with mass 0.55 kg, which is initially at rest. Cart A stops after the collision and Cart B begins to move.

What is the final kinetic energy of Cart B?

If A stopped and it was elastic then the B has the same as A had

(1/2)(.55)(v^2)

.06875

To find the final kinetic energy of Cart B, we need to use the principles of conservation of momentum and conservation of kinetic energy.

Let's start by calculating the initial momentum of the system. The initial momentum is equal to the sum of the masses of both carts multiplied by their respective velocities. Since Cart A is moving towards Cart B and Cart B is initially at rest, the initial velocity of Cart A is non-zero, and the initial velocity of Cart B is zero.

The initial momentum is given by:

Initial momentum = (mass of Cart A * velocity of Cart A) + (mass of Cart B * velocity of Cart B)

Plugging in the values:

Initial momentum = (0.55 kg * velocity of Cart A) + (0.55 kg * 0)

Since Cart A stops after the collision, its final velocity is zero. Therefore:

Initial momentum = 0.55 kg * 0 = 0

According to the conservation of momentum, the total momentum before and after the collision should be the same. So, the final momentum of the system will also be zero.

Final momentum = 0

Now, let's calculate the final kinetic energy of Cart B. The kinetic energy is given by the formula:

Kinetic energy = 1/2 * mass * velocity^2

Since Cart B is the only cart moving after the collision, its mass and velocity will determine its final kinetic energy. We know the mass of Cart B is 0.55 kg, but we need to find its final velocity.

Since the momentum of the system is conserved, we have:

Initial momentum = Final momentum

(0.55 kg * velocity of Cart A) + (0.55 kg * 0) = 0

0.55 kg * velocity of Cart A = 0

Since the velocity of Cart A is zero (it stops after the collision), we have:

0.55 kg * 0 = 0

So, the final velocity of Cart B is also zero.

Plugging in the values, the final kinetic energy of Cart B is:

Kinetic energy = 1/2 * mass * velocity^2
Kinetic energy = 1/2 * 0.55 kg * 0^2
Kinetic energy = 1/2 * 0.55 kg * 0
Kinetic energy = 0

Therefore, the final kinetic energy of Cart B is 0.