The magnetic force (Vector FM)on a particle in a magnetic field is found by Vector FM = Vector I × Vector B, Vector I is the charge multiplied by the velocity of a charged particle and Vector B the strength of the magnetic field, in Tesla (T). An electron accelerates from rest to the right, in a horizontally directed electric field. The electron then leaves the electric field at a speed of 4.0 × 106, entering a magnetic field of magnitude 0.20 T (Tesla) directed into the screen. Calculate the magnitude and direction of the magnetic force on the electron. (Charge on an electron: q = 1.6 × 10-19)

Given:

- Charge on an electron (q) = 1.6 × 10^-19 C
- Initial velocity of the electron (Vi) = 0 (rest)
- Final velocity of the electron (Vf) = 4.0 × 10^6 m/s
- Magnetic field strength (B) = 0.20 T (directed into the screen)

To find the magnitude and direction of the magnetic force on the electron, we can use the formula:

Vector FM = Vector I × Vector B

Since the charge (q) is multiplied by the velocity (V), we can calculate the Vector I:

Vector I = q * V
= (1.6 × 10^-19 C) * (4.0 × 10^6 m/s)

Now we can calculate the magnitude and direction of Vector I:

Magnitude of Vector I = Charge * Velocity
= (1.6 × 10^-19 C) * (4.0 × 10^6 m/s)

The direction of Vector I will be the same as the initial velocity, which is to the right.

Now, we can calculate the magnetic force:

Vector FM = Vector I × Vector B

Since Vector I is to the right and Vector B is into the screen (or out of the screen), we can use the right-hand rule to find the direction of the resulting force:

- Extend the thumb, index finger, and middle finger of your right hand, perpendicular to each other.
- Point the thumb in the direction of Vector V (initial velocity).
- Point the index finger in the direction of Vector B (magnetic field).
- The direction in which the middle finger points (perpendicular to both the thumb and index finger) will give the direction of Vector FM (magnetic force).

Now, we can calculate the magnitude of Vector FM:

Magnitude of Vector FM = | Vector I | * | Vector B |
= Magnitude of Vector I * Magnitude of Vector B

Thus, plug in the values to get the final solution.

To calculate the magnitude and direction of the magnetic force on the electron, you can follow these steps:

Step 1: Determine the values of the variables in the given problem.
- Charge on an electron (q) = 1.6 × 10^-19 C (Coulombs)
- Initial velocity of the electron (Vi) = 0 m/s (electrons start from rest)
- Final velocity of the electron (Vf) = 4.0 × 10^6 m/s
- Magnetic field strength (B) = 0.20 T (Tesla)

Step 2: Calculate the value of the charge multiplied by the velocity of the electron (Vector I).
- Vector I = q * Vi (Vector I is a vector with both magnitude and direction)
- Since the electron starts from rest, its initial velocity is zero, so Vector I = q * 0 = 0 (Vector I = 0)

Step 3: Calculate the value of the charge multiplied by the final velocity of the electron (Vector I).
- Vector I = q * Vf (Vector I is a vector with both magnitude and direction)
- Plugging in the values, we have Vector I = (1.6 × 10^-19 C) * (4.0 × 10^6 m/s) = 6.4 × 10^-13 C·m/s

Step 4: Calculate the magnetic force (Vector FM) using the given formula.
- Vector FM = Vector I × Vector B (Vector FM is a vector with both magnitude and direction)
- Since Vector I = 0 in this case (as calculated in step 2), the cross product of Vector I and Vector B will be zero, so Vector FM = 0

Therefore, the magnitude of the magnetic force on the electron is zero, and the direction of the magnetic force is non-existent (no force is acting on the electron).

well, what are the vectors I and B?

they have given you the magnitudes and directions. Turn that into i,j,k components.

When Gina looks at an old photograph of her high school graduating class, a flood of memories comes rushing back. Gina finds herself going from one memory to the next. According to memory research, this process is referred to as ____________________.