A small candle with a mass of 6.0 g was completely burned. the heat produced heated 100 g of water from 23.0 to 33.0 Celsius if 200 g were heated by the same candle the temperature change of the water would be:

I don't understand this question

You change the T of 100 g water by 10 C.

So how much will T change for 200 g water? Could that be 5 C?

To answer this question, we need to use the concept of heat transfer and calorimetry.

The heat produced by burning the candle is transferred to the water, resulting in a temperature change. The heat transfer equation states that the heat Q transferred is proportional to the mass m of the substance being heated and the change in temperature ΔT:

Q = mcΔT

Where Q is the heat transfer in Joules (J), m is the mass in grams (g), c is the specific heat capacity, and ΔT is the change in temperature in degrees Celsius (°C).

In the given situation, we know that a small candle with a mass of 6.0 g completely burned and heated 100 g of water from 23.0 to 33.0 Celsius. Let's calculate the heat transfer for this scenario:

Q = mcΔT
Q = (100 g) (4.18 J/g°C) (33.0°C - 23.0°C)
Q = (100 g) (4.18 J/g°C) (10.0°C)
Q = 4180 J

So, the heat transferred to the water in the first scenario is 4180 Joules.

Now, if 200 g of water were heated by the same candle, we can use the same equation to calculate the temperature change:

Q = mcΔT
4180 J = (200 g) (4.18 J/g°C) ΔT
4180 J = (836 J°C) ΔT
ΔT = 4180 J / 836 J/°C
ΔT = 5°C

Therefore, if 200 g of water were heated by the same candle, the temperature change of the water would be 5 degrees Celsius.