Evaluate by U-substitution: the integral of xcubedroot(x-2) dx
x∛(x-2) dx
let
u^3 = x-2
x = u^3+2
3u^2 du = dx
now the integrand is
(u^3+2)(u)(3u^2 du)
and that's just a b unch of powers.
let
u^3 = x-2
x = u^3+2
3u^2 du = dx
now the integrand is
(u^3+2)(u)(3u^2 du)
and that's just a b unch of powers.