A certain force gives mass m1 an acceleration of 13.0 m/s2 and mass m2 an acceleration of 3.6 m/s2.
1) What acceleration would the force give to an object with a mass of (m2-m1)?
2) A certain force gives mass m1 an acceleration of 13.0 m/s2 and mass m2 an acceleration of 3.6 m/s2. What acceleration would the force give to an object with a mass of (m2-m1)?
F=13.0m1 F=3.6m2 therefore 3.6m2=13m1 m2=3.61m1 F=(3.61m1-m1)a F=2.61m1a m1=F/13 F=2.61*(F/13)a 2.61a=13 a=4.98m/s^2
To solve these questions, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Let's denote the force by F, mass m1 by m1, and mass m2 by m2.
1) To find the acceleration of an object with a mass of (m2-m1), we can use the formula F = m × a, where m is the mass and a is the acceleration. In this case, the force acting on the object is still F.
We have the following information:
- For mass m1, the force gives an acceleration of 13.0 m/s^2.
- For mass m2, the force gives an acceleration of 3.6 m/s^2.
Using Newton's second law, we can set up the equations:
F = m1 × 13.0 m/s^2 ..........(Equation 1)
F = m2 × 3.6 m/s^2 ..........(Equation 2)
Now, let's solve these equations simultaneously. By dividing Equation 1 by Equation 2, you get:
(m1 × 13.0 m/s^2) / (m2 × 3.6 m/s^2) = 1
Now, let's multiply both sides by (m2 - m1):
(m1 × 13.0 m/s^2) / (m2 × 3.6 m/s^2) × (m2 - m1) = m2 - m1
The left side of the equation represents the acceleration of an object with a mass of (m2 - m1). So, the acceleration would be equal to m2's acceleration minus m1's acceleration.
Therefore, the answer to question 1 is that the acceleration of an object with a mass of (m2-m1) would be (3.6 m/s^2 - 13.0 m/s^2).
2) Based on the information provided in the question, we have already determined that the acceleration of an object with a mass of (m2-m1) is (3.6 m/s^2 - 13.0 m/s^2).
Therefore, the answer to question 2 is the same as in question 1: the acceleration of an object with a mass of (m2-m1) is (3.6 m/s^2 - 13.0 m/s^2).