An aeroplane is taking off from landing field has to run 500 metres.it leaves the ground in 10 seconds.what is the acceleration?
To calculate the acceleration of the airplane, we can use the formula for acceleration:
Acceleration (a) = Change in velocity (Δv) / Time (t)
In this case, the change in velocity is the difference between the final velocity (v) when the airplane leaves the ground and the initial velocity (u) when it starts running. The time taken (t) is given as 10 seconds. Let's assume that the initial velocity (u) is 0 since the airplane is starting from rest.
We can use the formula for velocity (v) to find the final velocity when the airplane leaves the ground:
v = u + at,
where:
v = final velocity (unknown),
u = initial velocity (0),
a = acceleration (unknown),
t = time taken (10 seconds).
Since the initial velocity is 0, the formula simplifies to:
v = at.
Given that the distance covered (s) is 500 meters, we can use the formula for distance (s) to relate it with acceleration (a):
s = ut + (1/2)at^2.
Rearranging the formula, we have:
2s = 2at^2.
Substituting the values, we get:
2(500) = 2a(10^2).
Simplifying further:
1000 = 200a.
Dividing both sides of the equation by 200:
a = 1000 / 200 = 5 m/s^2.
Therefore, the acceleration of the airplane is 5 meters per second squared.
since the distance covered by constant acceleration a is
s = 1/2 at^2, we have
1/2 a*10^2 = 500
a = 10 cm/s^2
50 m/s is the average speed during takeoff, not the acceleration.
500m/10 seconds
= 50m/second