A 76.6-kg person stands on a scale in an elevator. What is the apparent weight when the elevator is (a) accelerating upward with an acceleration of 1.94 m/s2, (b) moving upward at a constant speed, and (c) accelerating downward with an acceleration of 1.15 m/s2?
I've already figured out part (b) which is just 750.68 N, I need help with parts (a) and (c)
Just add/subtract the given acceleration to gravity. Then as usual, F=ma, where a is the net acceleration.posted by Steve