A hypothetical planet has a mass 1.55 times that of Earth, but the same radius.

What is g near its surface?

what was the ecuation?

To calculate the acceleration due to gravity (g) near the surface of a planet, we can use the formula:

g = G * (m / r^2)

Where:
- g is the acceleration due to gravity near the planet's surface
- G is the gravitational constant (approximately 6.67430 × 10^-11 N m^2 / kg^2)
- m is the mass of the planet
- r is the radius of the planet

In this case, the mass of the hypothetical planet is 1.55 times that of Earth, and it has the same radius as Earth. Since we know the ratio of the masses but do not have the exact values, we can use Earth's mass and radius as a reference.

The mass of Earth is approximately 5.972 × 10^24 kg, and its radius is approximately 6,371 km (6,371,000 meters).

Now, let's calculate the acceleration due to gravity near the surface of the hypothetical planet using these values:

m (hypothetical planet) = 1.55 * m (Earth)
= 1.55 * 5.972 × 10^24 kg

r (hypothetical planet) = r (Earth)
= 6,371,000 meters

Substituting these values into the formula, we have:

g = G * ((1.55 * 5.972 × 10^24 kg) / (6,371,000 meters)^2)

Calculating this expression will provide the acceleration due to gravity near the surface of the hypothetical planet.

1.62 m/s^2