Algebra 2

The third and sixth terms of a geometric sequence are -75 and -9375 respectively. Find the first term, the common ratio, and an explicit rule for the nth term.

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  1. t3 = ar^2 = -75
    t6 = ar^5 = -9375
    divide them
    r^3 = 125
    r = 5

    in ar^2 = -75
    a(25) = -75
    a = -3

    term(n) = -3(5)^(n-1)

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    posted by Reiny

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