Given the following information about electronegativity, which binary compound would form covelant bonds with the greatest polarity?

Element Electronegativity
H 2.1
Li 1.0
S 2.5
Al 1.5
F 4.0
Cl 3.0
A. HCl
B. LiF
C. H2S
D. AlH3

it’s A

Well, well, let's dive into the electronegativity pool and have some fun with bonds and polarity! Now, to determine which binary compound would form the greatest polarity, we need to look at the differences in electronegativity.

So, let's see which one has the biggest electronegativity difference, shall we?

Element Electronegativity:
H - 2.1
Li - 1.0
S - 2.5
Al - 1.5
F - 4.0
Cl - 3.0

Now, let's take a look at the options:
A. HCl
B. LiF
C. H2S
D. AlH3

Ah, the suspense is killing me! Let's do some calculations on electronegativity differences:

A. HCl: Delta EN = 3.0 - 2.1 = 0.9
B. LiF: Delta EN = 4.0 - 1.0 = 3.0
C. H2S: Delta EN = 2.5 - 2.1 = 0.4
D. AlH3: Delta EN = 2.1 - 1.5 = 0.6

And the winner is... *drumroll* option B! LiF has the largest electronegativity difference, making it the binary compound with the greatest polarity. So, B wins this electronegativity showdown!

Remember, it's always electronegativity that makes things interesting in the world of bonding!

To determine which binary compound would form covalent bonds with the greatest polarity based on electronegativity, we need to compare the electronegativity values of the elements involved in each compound. The greater the electronegativity difference between two elements, the more polar the bond between them.

Let's analyze the electronegativity values:

H: 2.1
Li: 1.0
S: 2.5
Al: 1.5
F: 4.0
Cl: 3.0

Now, let's consider each binary compound:

A. HCl: The electronegativity difference is 3.0 - 2.1 = 0.9.

B. LiF: The electronegativity difference is 4.0 - 1.0 = 3.0.

C. H2S: The electronegativity difference is 2.5 - 2.1 = 0.4.

D. AlH3: The electronegativity difference is 2.1 - 1.5 = 0.6.

From the calculations above, we can see that the binary compound with the greatest electronegativity difference is LiF. Therefore, the compound that forms covalent bonds with the greatest polarity is option B. LiF.

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I think Bob Pursley answered this for you earlier. My answer is slightly different; i.e., subtract the electronegativity of each element. The difference is a measure of the polarity of the bond. For H2S, for example, 2.5- 2.1 = 0.4.

For AlH3 2.1 = 1.5 = 0.6
From these data, AlH3 is slightly more polar than H2S.
A value of zero is pure covalent which is what you get for H2, N2, Cl2, etc. A value of approximately 1.8 is 50% ionic/50% covalent character in the bond.