what would the pressure be if box was turned so the smallest surface was touching ground. Box dimensions: length 25cm, width 10cm, height 4cm, mass 4kg
To calculate the pressure exerted when the smallest surface of the box is touching the ground, we need to know the contact area and the weight of the box.
First, let's find the contact area of the box when the smallest surface is touching the ground. The dimensions of the box are provided as length, width, and height. The smallest surface will have dimensions of length and width.
In this case, the length is 25 cm and the width is 10 cm, so the contact area is given by:
Contact Area = Length × Width
Contact Area = 25 cm × 10 cm
Now we can calculate the contact area:
Contact Area = 250 cm²
Next, we need to find the weight of the box. The mass of the box is given as 4 kg, and we can find the weight by applying the gravitational acceleration of 9.8 m/s²:
Weight = Mass × Gravity
Weight = 4 kg × 9.8 m/s²
Now we can calculate the weight:
Weight = 39.2 N
Finally, we can determine the pressure exerted by the box when the smallest surface is touching the ground. Pressure is defined as the force exerted per unit area:
Pressure = Weight / Contact Area
Now we can calculate the pressure:
Pressure = 39.2 N / 250 cm²
To ensure the units are consistent, we need to convert the contact area from cm² to m²:
Pressure = 39.2 N / (250 cm² × (1 m / 100 cm) × (1 m / 100 cm))
Pressure = 1.568 N / (0.025 m²)
Now let's calculate the pressure:
Pressure = 62.72 Pa
Therefore, the pressure exerted when the smallest surface of the box is touching the ground is 62.72 Pascal.