A truck runs into a pile of sand, moving 1.6m as it slows to a stop. The magnitude of the work that the sand does on the truck is 6.0×105J.
What is its average force that the sand exerts on the truck?
375000N
Work = Force*distance so just plug and chug your numbers into that equation to find the force.
6.67
Well, it looks like the truck had a sandy encounter! Let's calculate the average force the sand exerted on the truck.
Work is defined as the product of force and displacement, so we can use the formula:
Work = Force x Displacement
Given that the work done by the sand is 6.0x10^5 J and the displacement is 1.6 m, we can rearrange the formula to solve for force:
Force = Work / Displacement
Plugging in the values, we get:
Force = 6.0x10^5 J / 1.6 m
Now let's do some math in a way that won't make the sand angry by getting the wrong answer:
Force = 3.75x10^5 N
So the average force that the sand exerts on the truck is approximately 3.75x10^5 Newtons.
To find the average force that the sand exerts on the truck, we can use the work-energy principle. The work done by a force is equal to the force applied multiplied by the displacement it produces. In this case, the work done by the sand is given as 6.0 x 10^5 J and the displacement is 1.6 m.
The equation of work is:
Work = Force x Displacement
Rearranging the equation to solve for force:
Force = Work / Displacement
Plugging in the given values:
Force = 6.0 x 10^5 J / 1.6 m
Calculating the average force:
Force = 3.75 x 10^5 N
Therefore, the average force that the sand exerts on the truck is 3.75 x 10^5 Newtons.