"Find the total energy lost by the contents of a Styrofoam picnic cooler when a 3.60 kg block of ice placed inside the cooler completely melts (at 0 Celsius). The ice had an initial temperature of -10.00 Celsius."
My ans are
q1=72360J n q2=21672
q=94032J
But one confussion don't Ive to find the moles for water and then multiply by heat of fusion?
Yes you need to melt the ice. You may or may not need to convert to mols. Why didn't you type your work and I could find the problem almost instantly. As it is we're well into 2-3 hours for this.
I agree with your 72,360 J for heat to move T from -10 to zero c.
Where (how) did you get 21,672?
To find the total energy lost by the contents of the Styrofoam picnic cooler when the ice melts, we need to consider two steps: first, raising the temperature of the ice from -10.00°C to 0°C and then melting the ice at its melting temperature of 0°C.
Let's break down the steps:
Step 1: Raising the temperature of the ice from -10.00°C to 0°C
To determine the energy required to raise the temperature, we use the specific heat capacity (c) of ice. The specific heat capacity of ice is 2.09 J/g°C.
The mass of the ice (m) is 3.60 kg, which is equal to 3600 grams.
The change in temperature (ΔT) is calculated as follows:
ΔT = final temperature - initial temperature
= 0°C - (-10.00°C)
= 10.00°C
Multiply the mass (m), specific heat capacity (c), and change in temperature (ΔT) to find the energy required for this step (q1):
q1 = m * c * ΔT
q1 = 3600 g * 2.09 J/g°C * 10.00°C
= 75,240 J
So, the energy required to raise the temperature is 75,240 Joules.
Step 2: Melting the ice at 0°C
To determine the energy required to melt the ice, we use the heat of fusion (ΔHf) of water. The heat of fusion of water is 334 J/g.
The mass of the ice (m) is still 3.60 kg, which is equal to 3600 grams.
Multiply the mass (m) and the heat of fusion (ΔHf) to find the energy required for this step (q2):
q2 = m * ΔHf
q2 = 3600 g * 334 J/g
= 1,202,400 J
So, the energy required to melt the ice is 1,202,400 Joules.
Finally, we can find the total energy lost by adding both energy values:
Total Energy lost (q) = q1 + q2
= 75,240 J + 1,202,400 J
= 1,277,640 J
The total energy lost by the contents of the Styrofoam picnic cooler is 1,277,640 Joules.
Note: In your answer, q2 is incorrect. The value you mentioned (21672 J) seems to be an error.