In an acid-base neutralization reaction 25 mL of 0.4 M NaOH reacts with 50.00 mL of H2SO4 solution. Calculate the concentration of the H2SO4 solution?

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

mols NaOH = M x L = ?
mols H2SO4 = 1/2 mols NaOH from the coefficients in the balanced equation.
M H2SO4 = mols H2SO4/L H2SO4

To calculate the concentration of the H2SO4 solution, we can use the concept of stoichiometry. In a neutralization reaction, the number of moles of acid is equivalent to the number of moles of base.

First, let's determine the number of moles of NaOH used in the reaction:
Moles of NaOH = Volume of NaOH (in L) × Concentration of NaOH (in M)
= 25 mL × (1 L / 1000 mL) × 0.4 M
= 0.01 mol

Since the reaction is 1:1 between NaOH and H2SO4, the number of moles of H2SO4 is also 0.01 mol.

Next, let's calculate the concentration of H2SO4:
Concentration of H2SO4 = Moles of H2SO4 / Volume of H2SO4 (in L)
= 0.01 mol / (50.00 mL × (1 L / 1000 mL))
= 0.2 M

Therefore, the concentration of the H2SO4 solution is 0.2 M.