the change in velocity takes place in 10 sec interval. What is the magnitude, the algebraic sign and the direction of the average acceleration in each interval?

At the beginning of the interval a body is moving to the right along the x-axis at 5 ft/sec, and at the end of the interval, it is moving towards the right at 20 ft/sec.

a = (V-Vo)/t = Acceleration in Ft./s^2

V = 20 Ft/s.
Vo = 5 Ft/s.

To find the average acceleration, we need to calculate the change in velocity and divide it by the time interval. Given the initial velocity is 5 ft/sec and the final velocity is 20 ft/sec, the change in velocity is (20 ft/sec - 5 ft/sec) = 15 ft/sec.

The time interval is given as 10 seconds. Therefore, the average acceleration is calculated by dividing the change in velocity by the time interval: (15 ft/sec) / (10 sec) = 1.5 ft/sec².

The magnitude of the average acceleration is 1.5 ft/sec². The algebraic sign refers to the positive or negative nature of the acceleration. In this case, since the velocities are both positive (moving to the right), the algebraic sign is positive.

The direction of the average acceleration can be determined by looking at the initial and final velocities. In this case, since the body is moving towards the right both at the beginning and at the end of the interval, the direction of the average acceleration is also towards the right.