An object has a velocity of 5.00 m/s at an angle of 30.0˚ north of east. If we define east as the +x direction and north as the +y direction, what is the magnitude of vy?
V = 5m/s[30o]
Vy = 5*sin30 = 2.5 m/s
To find the magnitude of vy, we need to break down the velocity into its x and y components.
Given:
Velocity magnitude = 5.00 m/s
Angle north of east = 30.0˚
To find vy, we use the trigonometric relationship:
sin(θ) = vy / velocity magnitude
Rearranging the formula, we get:
vy = velocity magnitude * sin(θ)
Substituting the given values:
vy = 5.00 m/s * sin(30.0˚)
Using a calculator, we compute:
vy ≈ 2.50 m/s
Therefore, the magnitude of vy is approximately 2.50 m/s.
To find the magnitude of vy, we first need to understand the given information. The object has a velocity of 5.00 m/s at an angle of 30.0˚ north of east. This means that the object's velocity has a component in the y-direction (north) and a component in the x-direction (east).
To find the magnitude of vy, we need to find the component of the velocity in the y-direction. We can use trigonometry to do this.
Given that the velocity makes an angle of 30.0˚ north of east, we can break down the velocity into its x-component (vx) and y-component (vy) using the following relationships:
vx = v * cos(theta)
vy = v * sin(theta)
Where v is the magnitude of the velocity (given as 5.00 m/s) and theta is the angle (given as 30.0˚).
Now, let's calculate the magnitude of vy.
Using the formula vy = v * sin(theta):
vy = 5.00 m/s * sin(30.0˚)
Using a calculator, we find:
vy = 5.00 m/s * 0.5
vy = 2.50 m/s
Therefore, the magnitude of vy is 2.50 m/s.