1.2048g sample of impure Na2CO3 is dissolved and allowed to react with a solution of CaCl2 resulting CaCO3 after precipitation, filtaration and drying was found to weight 1.0362g. calculate the percentage purity of Na2CO3
1.0326g CaCO3 x (molar mass Na2CO3/molar mass CaCO3) = grams Na2CO3.
% purity = (grams Na2CO3/mass sample)*100 = ?
To calculate the percentage purity of Na2CO3, we need to determine the mass of pure Na2CO3 in the sample.
1. The mass of the impure sample of Na2CO3 is 1.2048g.
2. After the reaction, filtration, and drying, the mass of the CaCO3 precipitate is 1.0362g.
Since the reaction between Na2CO3 and CaCl2 results in the formation of CaCO3, we can assume that all the CaCO3 formed came from the Na2CO3 in the sample.
3. To find the mass of pure Na2CO3, we subtract the mass of CaCO3 from the initial mass of the sample.
Mass of pure Na2CO3 = Initial mass of the sample - Mass of CaCO3
Mass of pure Na2CO3 = 1.2048g - 1.0362g
Mass of pure Na2CO3 = 0.1686g
4. Finally, we can calculate the percentage purity of Na2CO3 by dividing the mass of pure Na2CO3 by the initial mass of the sample and multiplying by 100.
Percentage purity = (Mass of pure Na2CO3 / Initial mass of the sample) x 100
Percentage purity = (0.1686g / 1.2048g) x 100
Percentage purity ≈ 13.99%
Therefore, the percentage purity of Na2CO3 in the sample is approximately 13.99%.
To calculate the percentage purity of Na2CO3, you need to determine the mass of pure Na2CO3 in the sample and divide it by the initial mass of the impure sample, then multiply by 100.
Given:
Mass of impure Na2CO3 sample = 1.2048g
Mass of CaCO3 after precipitation, filtration, and drying = 1.0362g
First, we need to find the mass of pure Na2CO3 in the sample. To do this, we need to determine the mass of CaCO3 formed and then convert it back to Na2CO3.
The balanced chemical equation for the reaction between Na2CO3 and CaCl2 is:
Na2CO3 + CaCl2 -> CaCO3 + 2NaCl
From the equation, we see that 1 mole of Na2CO3 produces 1 mole of CaCO3. Therefore, the molar mass of Na2CO3 is equal to the molar mass of CaCO3.
The molar mass of CaCO3 is:
1 mol Ca + 1 mol C + 3 mol O = 40.08 g + 12.01 g + (3 * 16.00 g) = 100.09 g/mol
Now, we can calculate the number of moles of CaCO3 formed:
Number of moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Number of moles of CaCO3 = 1.0362 g / 100.09 g/mol
Next, since the molar ratio of Na2CO3 to CaCO3 is 1:1, the number of moles of Na2CO3 is also equal to the number of moles of CaCO3.
Number of moles of Na2CO3 = Number of moles of CaCO3
Finally, we can calculate the mass of pure Na2CO3 in the sample:
Mass of pure Na2CO3 = Number of moles of Na2CO3 * Molar mass of Na2CO3
Now, we can calculate the percentage purity of Na2CO3:
Percentage purity = (Mass of pure Na2CO3 / Mass of impure sample) * 100
I'll calculate the answer for you.