Ethylene gas (C2H2) can be formed from the reaction of calcium carbide (CaC2) with water. What is the reaction rate if 14.2 grams of ethylene gas are produced over 4.00 seconds? The units are mol/s.
I don't see any way to calculate concentration. You have grams and you can get mols, but mols/L = ?
rate = d(C2H2)/time.
To determine the reaction rate in mol/s, we need to first calculate the number of moles of ethylene gas produced and then divide it by the time taken.
Step 1: Calculate the number of moles of ethylene gas produced
To do this, we need to know the molar mass of ethylene gas. The molar mass of ethylene (C2H2) is:
2(atomic mass of Carbon) + 2(atomic mass of Hydrogen)
= 2(12.01 g/mol) + 2(1.01 g/mol)
= 24.02 g/mol + 2.02 g/mol
= 26.04 g/mol
Now we can calculate the number of moles of ethylene gas produced:
moles of ethylene = mass of ethylene / molar mass of ethylene
= 14.2 g / 26.04 g/mol
= 0.545 mol
Step 2: Calculate the reaction rate
The reaction rate is given by the equation:
reaction rate = moles of ethylene gas / time
In this case, the moles of ethylene gas produced is 0.545 mol, and the time is 4.00 seconds. Therefore, we can calculate the reaction rate as follows:
reaction rate = 0.545 mol / 4.00 s
= 0.136 mol/s
So, the reaction rate is 0.136 mol/s.