pre cal 11

hi so i am stuck at this question that is asking about arithmetic sequence .

Five fence posts are equally spaced between two corner posts that are 42 meter apart. how far apart are the five fence posts.

i know the answer is 7m but i don't know how plus i know the equation for the arithmetic sequence is
tn=t1(n-1)d, but how does it apply to this question?

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  1. a=0(starting from a corner pole1) no of poles=n=72 t7=42(corner pole 2) d=spacing 42=0+d(7-1) 6d=42 d=7m

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  2. There are 7 posts including the two end ones.
    That means six equal spaces between posts
    42/6 = 7 meters

    (note, number of spaces = number of posts - 1)

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  3. oh my god thank you i makes sense now

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