Physics Dynamics

A person stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.69 of the person's regular weight. Calculate the magnitude of the acceleration of the elevator.

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  1. m= 0.69

    a=mg-g

    a=(0.69)(9.80)-9.80

    a=-3.038 m/s^2

    Acceleration is 3.038 m/s^2 downward

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  2. cheese technique

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  3. no

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  4. A person stand on bathroom scale in motionless elevator. When elevator begins to move the briefly reads

    only 0.54 of the person's regular weight. Calculate acceleration of elevator.

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  5. Fnet = ma
    ma = Fn-Fg
    Fn = 0.69Fg = 0.69mg
    Fg = mg
    ma = 0.69mg - mg
    cancel out all m in equation and left with:
    a=0.69g-g
    a=-.31g=-.31*9.8= -3.04 m/s^2
    ANSWER: a = -3.04 m/s^2

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