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Describe the preparation of 100 mL of 6.0 M HCL from a concentrated solution that has a specific gravity of 1.18 and is 37% (w/w) HCL

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  1. Ans.: (1000mL/1L)(1.18 g/mL)(0.37)(1mol HCl/36.5 g HCl) = 11.96 M

    We want to make 100 mL of 6.0 M: 600 mmol HCl required

    V x M = V x M 100 mL x 6.0 mmol/mL = V x 11.96 M

    V = 50.17 mL Therefore, take 50 mL of the conc. HCl and dilute to exactly 100.0 mL with water.

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