A car starting from rest accelerates. Uniformly for 5sec reaches a velocity of 12m.s-1.it then maintains this velocity for 4sec,after which the brakes are applied to bring the car to rest over a distance of 24m. 1.calculate the uniform acceleration experienced by the car in the first 5sec?
v = 0 + a t
12 = a (5)
a = 12/5
Is that the whole question? Surely they ask about the deceleration as well?
d = Vi t + (1/2) a t^2
so
24 = 12 t + (1/2) a t^2
v = Vi + a t
so
0 = 12 + a t
diagram
To calculate the uniform acceleration experienced by the car in the first 5 seconds, we can use the following formula:
Acceleration = (Final Velocity - Initial Velocity) / Time
Given:
Initial Velocity (u) = 0 m/s (starting from rest)
Final Velocity (v) = 12 m/s
Time (t) = 5 seconds
Using the formula, we can substitute the values to find the acceleration:
Acceleration = (12 m/s - 0 m/s) / 5 seconds
Acceleration = 2.4 m/s^2
Therefore, the uniform acceleration experienced by the car in the first 5 seconds is 2.4 m/s^2.