a BALL IS THROWN UPWARD WITH AN INITIAL VELOCITY OF 9.8 M/S FROM THE TOP OF A BUILDING.
FILL A TABLE BELOW SHOWING THE BALLS POSITION,VELOCITY, and ACCELERATION AT THE END OF EACH OF THE 1ST 4SEC OF MOTION
TIME(s) POSITION(M) VELOCITY(M/S)
1
2
3
4
Acceleration (M?S^2)
Fill in the graph
To fill in the table, we need to analyze the motion of the ball and use the equations of motion. Let's break down the problem step by step.
1. Position (m):
The position of the ball can be calculated using the equation:
position = initial position + (initial velocity * time) + (0.5 * acceleration * time^2)
In this case, the initial position of the ball is the top of the building, so it is assumed to be zero.
For time=1s:
position = 0 + (9.8 * 1) + (0.5 * (-9.8) * (1^2))
For time=2s:
position = 0 + (9.8 * 2) + (0.5 * (-9.8) * (2^2))
Similarly, fill in the table for time=3s and time=4s using the same equation.
2. Velocity (m/s):
The velocity of the ball can be calculated using the equation:
velocity = initial velocity + (acceleration * time)
For time=1s:
velocity = 9.8 + (-9.8 * 1)
For time=2s:
velocity = 9.8 + (-9.8 * 2)
Similarly, fill in the table for time=3s and time=4s using the same equation.
3. Acceleration (m/s^2):
The acceleration is constant and equal to -9.8 m/s^2 since the ball is moving against the force of gravity.
For each row in the table, fill in the acceleration column with -9.8 m/s^2.
Once you have filled in the values in the table, you can create a graph by plotting time on the x-axis and position/velocity/acceleration on the y-axis. Connect the data points with a smooth curve to display the variations over time.
Note: It's important to recheck the calculations to ensure accurate results.