In a livestock research stations a new drug for a certain fowl disease is being tried. Samples of 36 fowls were diagnosed to have the disease. Twenty (20) fowls were treated with the drug and the rest were not.
(a) Calculate the probability that a fowl picked at random is
(i) Treated with the drug
(ii) Not treated with the drug
P(treat) = 20/36 = ?
P(not) = (36-20)/36 = ?
To solve this problem, we need to calculate the probabilities based on the given information.
(a)
(i) To calculate the probability that a fowl picked at random is treated with the drug, we need to find the ratio of the number of fowls treated with the drug to the total number of fowls.
Given information:
- Number of fowls diagnosed with the disease: 36
- Number of fowls treated with the drug: 20
Probability of a fowl being treated with the drug = (Number of fowls treated with the drug) / (Total number of fowls)
Probability of a fowl being treated with the drug = 20/36
Therefore, the probability that a fowl picked at random is treated with the drug is 20/36.
(ii) To calculate the probability that a fowl picked at random is not treated with the drug, we need to find the ratio of the number of fowls not treated with the drug to the total number of fowls.
Given information:
- Number of fowls diagnosed with the disease: 36
- Number of fowls treated with the drug: 20
Number of fowls not treated with the drug = Total number of fowls - Number of fowls treated with the drug
Number of fowls not treated with the drug = 36 - 20
Probability of a fowl being not treated with the drug = (Number of fowls not treated with the drug) / (Total number of fowls)
Probability of a fowl being not treated with the drug = 16/36
Therefore, the probability that a fowl picked at random is not treated with the drug is 16/36.