A ball is thrown into the air with the in initial upward velocity of 60 ft/s. It's height (h) in feet after t seconds is given by the function h=- -16t^2+60t+6. What will the height be at t=3 seconds?
my answer is 42 feet
is Steve correct with 42 feet?
Is he
he is
To find the height of the ball at t=3 seconds, we can substitute t=3 into the given function and evaluate h.
Given function: h = -16t^2 + 60t + 6
Replace t with 3:
h = -16(3)^2 + 60(3) + 6
First, simplify the expression within the parentheses:
h = -16(9) + 60(3) + 6
Perform the multiplications within the parentheses:
h = -144 + 180 + 6
Then, add/subtract the numbers:
h = 42
Therefore, the height of the ball at t=3 seconds is 42 feet.