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The (aq) solution with the lowest freezing temperature would be which of the following:

0.010M NaCl
0.020M NaCl
0.030M C6H1206
0.030M NaNO3
0.030M HC2H3O2

The NaCl and the NaNO3 break up into two particles each. The sugar does not, and the acetic acid hardly ionizes at all.

That changes the concentration of dissolved particles to..

0.020M NaCl
0.040M NaCl
0.030M C6H1206
0.060M NaNO3
0.030M HC2H3O2

So the answer is: Which has the higher concentration of particles?

is it 0.060M NaNO3 because it has the higher concentration of particles?

Yes.

Yes, you are correct. The (aq) solution with the highest concentration of particles will have the lowest freezing temperature. In this case, the solution with 0.060M NaNO3 has the highest concentration of particles because NaNO3 dissociates into three ions (Na+ and two NO3-) in solution. Therefore, it will have the lowest freezing temperature compared to the other solutions mentioned.