If 6.20 mol of calcium carbide (CaC2) reacts with an excess of water, how many moles of acetylene (C2H2), a gas used in welding, will be produced?
CaC2(s) + 2 H2O(l) Ca(OH)2(aq) + C2H2(g)
Use the coefficients in the balanced equation to convert anything to anything.
6.20 mol CaC2 x (1 mol C2H2/1 mol CaC2) = 6.20 x 1/1. = 6.20 mols C2H2.
To find out how many moles of acetylene (C2H2) will be produced when 6.20 mol of calcium carbide (CaC2) reacts with an excess of water, we need to use the balanced chemical equation provided.
From the equation:
1 mol of CaC2 reacts with 2 mol of H2O to produce 1 mol of C2H2.
Given that you have 6.20 mol of CaC2, you can use stoichiometry to calculate the number of moles of C2H2 produced.
Step 1: Set up a conversion factor using the ratio from the balanced equation.
1 mol CaC2 : 1 mol C2H2
Step 2: Multiply the given amount of CaC2 by the conversion factor.
6.20 mol CaC2 * (1 mol C2H2 / 1 mol CaC2) = 6.20 mol C2H2
Therefore, 6.20 mol of calcium carbide will produce 6.20 mol of acetylene.