A car speeds up from 12 m/s to 20 m/s in 6.4s.If its mass is 1200 kg,what force must its engine provide ?

1500N

To determine the force that the engine must provide, we can use Newton's second law of motion, which states that force (F) is equal to the product of mass (m) and acceleration (a):

F = m * a

In this case, the car is initially traveling at a speed of 12 m/s and then increases its speed to 20 m/s over a time of 6.4 seconds. Therefore, the acceleration of the car can be calculated using the formula:

a = (vf - vi) / t

Where:
vf = final velocity = 20 m/s
vi = initial velocity = 12 m/s
t = time = 6.4 seconds

Substituting the given values, we can calculate the acceleration:

a = (20 - 12) / 6.4
a = 8 / 6.4
a = 1.25 m/s^2

Now, we can calculate the force required by substituting the mass (m = 1200 kg) and acceleration (a = 1.25 m/s^2) into the equation:

F = m * a
F = 1200 * 1.25
F = 1500 N

Therefore, the engine must provide a force of 1500 Newtons to accelerate the car from 12 m/s to 20 m/s in 6.4 seconds.

To calculate the force that the car's engine must provide, we can use Newton's second law of motion, which states that force (F) equals mass (m) times acceleration (a). In this case, we need to find the acceleration that the car goes through.

Since we know the initial velocity (u), final velocity (v), and time (t) taken for the car to accelerate, we can use the formula for acceleration:

a = (v - u) / t

Substituting the given values:

a = (20 m/s - 12 m/s) / 6.4 s
a = 8 m/s / 6.4 s
a = 1.25 m/s^2

Now that we have the acceleration, we can calculate the force:

F = m * a

Substituting the given mass:

F = 1200 kg * 1.25 m/s^2
F = 1500 N

Therefore, the car's engine must provide a force of 1500 Newtons.

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