what is the electric force exerted on a test charge of 3.86 x 10^-5 C if it is placed in an electric field of magnitude 1.75 x 10^4 N/C ?
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what is the electric force exerted on a test charge of 3.86 *10^-5c if it is placed an electric field of magnitude 1.75 *10^4 n/c
To find the electric force exerted on a test charge, you need to use the equation:
Electric force = Charge × Electric field
In this case, you are given the magnitude of the electric field (1.75 x 10^4 N/C) and the charge of the test charge (3.86 x 10^-5 C).
To find the electric force, simply multiply the charge by the electric field:
Electric force = (3.86 x 10^-5 C) × (1.75 x 10^4 N/C)
To multiply two numbers written in scientific notation, you need to multiply the coefficients (3.86 and 1.75) and add the exponents (10^-5 and 10^4).
Multiplying the coefficients, we get:
3.86 × 1.75 = 6.755
Adding the exponents, we get:
10^-5 + 10^4 = 10^(-5 + 4) = 10^-1
Therefore, the electric force exerted on the test charge is:
Electric force = 6.755 × 10^-1 N
So, the electric force exerted on the test charge is 0.6755 N.