The specific heat of iron is 0.498 J/g °C. If 341 J of heat is added to 154.1 g of iron at 25.0 °C, what is the new temperature of the iron?
q = mass Fe x specific heat Fe x (Tfinal-Tinitial)
q = 341 J. Solve for Tfinal.
To find the new temperature of the iron, we can use the equation:
q = m * c * ΔT
Where:
q = heat energy (J)
m = mass of the substance (g)
c = specific heat capacity of the substance (J/g °C)
ΔT = change in temperature (°C)
In this case, we know the heat energy (q), mass (m), specific heat capacity (c), and the initial temperature (25.0 °C). We need to find the change in temperature (ΔT) and then use it to calculate the new temperature.
To find ΔT, rearrange the equation:
ΔT = q / (m * c)
Substitute the given values into the equation:
ΔT = 341 J / (154.1 g * 0.498 J/g °C)
Now, calculate ΔT:
ΔT = 341 J / (76.6238 J/°C)
ΔT = 4.451 °C
The change in temperature is 4.451 °C. To find the new temperature, add this change to the initial temperature:
New temperature = Initial temperature + ΔT
New temperature = 25.0 °C + 4.451 °C
Therefore, the new temperature of the iron is approximately 29.451 °C.